> If a function you call returns an &mut you have no way > to tell Indeed, but also consider that a function can't return a `&mut` un...
> If a function you call returns an &mut you have no way > to tell Indeed, but also consider that a function can't return a `&mut` unless a `&mut` was passed in to it somehow. This means that the only way to implicitly introduce a `&mut` is via a method call like `foo.bar()` that takes `&mut self`, but also consider that it would be impossible to call the method here unless `foo` were explicitly declared as mutable to begin with. Given that mutable variables in Rust are relatively rare, these factors conspire to broadcast any mutable references quite clearly.
Posted by kibwen on Jun 6, 2015, 8:28 AM
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Raise real-world problems, find people facing the same issue, and discuss solutions.6,000 issues0 comments
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The biggest problem with having an LLM do this, from what I've observed of at least frontier models, is that the way they are trained...
The biggest problem with MOND is that it was hand-crafted with additional parameters simply to fit the data.
(My comment is about detached houses).
The biggest problem with this is that I can't run my company's own internal benchmarks against this API, because they will be trained int...
> steer Claude away from over-engineering parts of the system in response to hypothetical concerns.
Why is there no comparison with FLUX 3 Image?
> our Git monorepo was developing an annoying problem Sentences like this are so common from people using monorepos that I am convinced ...
Why is there no contact form?
> If a function you call returns an &mut you have no way > to tell Indeed, but also consider that a function can't return a `&mut` un...
> If a function you call returns an &mut you have no way > to tell Indeed, but also consider that a function can't return a `&mut` unless a `&mut` was passed in to it somehow. This means that the only way to implicitly introduce a `&mut` is via a method call like `foo.bar()` that takes `&mut self`, but also consider that it would be impossible to call the method here unless `foo` were explicitly declared as mutable to begin with. Given that mutable variables in Rust are relatively rare, these factors conspire to broadcast any mutable references quite clearly.
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